Probability

A new factory machine which manufactures computer chips is malfunctioning and has a 20% defect rate. If 5 chips are randomly selected from the machine, find the following probibilities: non are defective; less than 2 are defective.

Quote:

Originally Posted by batman123

A new factory machine which manufactures computer chips is malfunctioning and has a 20% defect rate. If 5 chips are randomly selected from the machine, find the following probibilities: non are defective; less than 2 are defective.

The probability that is would be correct is $.8$ , just let us use fractions which is $\frac{4}{5}$ . Now each 5 should be correct thus,
$\left(\frac{4}{5}\right)^5\approx .33$ .

For the second part you need to use the formula:
$_nC_mp^m(1-p)^{n-m}$ to determine the probability of something exactly happening out of a certain amount of times.

Over here you need it to be zero times exactly OR one time exactly of getting a defect. Zero times is the same as all 5 where non-defective which is the same as in the first problem is 33%. To determine of getting exactly one defect use $_5C_1\left(\frac{4}{5}\right)^4\left(\frac{1}{5} \right)^{5-4}\approx .4$ . Thus, the overall probability is the sum which is approximately 73%.

This is my 5:):)th post!!

Thanks!

Thanks!!! for all your help :D

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