Combination Problem, I think!

I have an interview panel made of:

1 Manager

1 Human Resource person

1 Supervisor

I have 5 managers to choose from

I have 6 Human Resource people to choose from

I have 7 supervisors to choose from

How many combinations could make up the interview panel.

Since order does not matter, I know it is not a permutation problem. How do I set up this problems???

Thanks,

Karies4083

Re: Combination Problem, I think!

Quote:

Originally Posted by

**karies4083** I have an interview panel made of:

1 Manager

1 Human Resource person

1 Supervisor

I have 5 managers to choose from

I have 6 Human Resource people to choose from

I have 7 supervisors to choose from

How many combinations could make up the interview panel.

Since order does not matter, I know it is not a permutation problem. How do I set up this problems???

$\displaystyle 5\cdot 6\cdot 7$ simple multiplication.

Re: Combination Problem, I think!

Re: Combination Problem, I think!

What if we change it up a bit:

Need 1 manager, 2 human resource persons, and 1 supervisor. Does this matter to the problem???

Thanks,

karies4083

Re: Combination Problem, I think!

Quote:

Originally Posted by

**karies4083** What if we change it up a bit:

Need 1 manager, 2 human resource persons, and 1 supervisor. Does this matter to the problem???

Thanks,

karies4083

$\displaystyle 5\cdot\binom{6}{2}\cdot 7$

Re: Combination Problem, I think!

Re: Combination Problem, I think!

Quote:

Originally Posted by

**karies4083** 525?

Correct.