A contestant on the game show called "A Diamond for your Wife" gets to select 5 diamonds from a box. The box contains 20 diamonds of which 8 are fake and 12 are real. Regardless of how many real diamonds the contestant has after his selection he can only take one home for his wife. A second contestant then gets to select from the remaining 15 diamonds from the box. But only gets to select one diamond.
What is the probability that this second contestant selects a real diamond?
I don't understand why the following reasoning is wrong:
Let F be the event where the diamond picked was fake and let R be the event where the diamond picked was real.
Thus, the first contestant could get 0F, 1F, 2F, 3F, 4F, 5F.
If the first contestant gets 0F, then that means he took 5R, thus the second contestant has a probability of 7/15 of getting 1R as there are now 7 R left out of the 15 diamonds.
Likewise if the first contestant gets 1F, then that means he took 4R, thus the second contestant has a probability of 8/15 of getting 1R.
This process continues until the first contestant picks 5F in which case the probability of the second contestant has a probability of 12/15 of getting 1R.
So the total probability is 7/15 + 8/15 + ... + 12/15 but clearly this is greater than 1, where did I go wrong?