]How would you solve

lim as x -> infinity f^{-1}( x^{2}+ 2 x + 1)

?

Thanks!

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- Jun 17th 2012, 01:36 PMkwonypooHow to take limits of inverse functions!
]How would you solve

lim as x -> infinity f^{-1}( x^{2}+ 2 x + 1)

?

Thanks! - Jun 17th 2012, 02:06 PMpickslidesRe: How to take limits of inverse functions!
Why not just find $\displaystyle f^{-1} (x^2+2x+1) $ ?

- Jun 17th 2012, 02:08 PMskeeterRe: How to take limits of inverse functions!
$\displaystyle f(x) = x^2 +2x + 1 = (x+1)^2$

restricting the domain of f(x) to x__>__-1

$\displaystyle f^{-1}(x) = \sqrt{x} - 1$

the inverse is unbounded as $\displaystyle x \to \infty$

I'm hoping you don't have confusion between inverse and reciprocal functions. - Jun 17th 2012, 05:11 PMHallsofIvyRe: How to take limits of inverse functions!
What you wrote was $\displaystyle \lim_{x\to\infty} f^{-1}(x^2+ 2x+ 1)$ which we cannot help you with because you did not tell us what "f" is. Skeeter assumed you

**meant**that $\displaystyle f(x)= x^2+ 2x+ 1$ and that you want to find $\displaystyle \lim_{x\to\infty} f^{-1}(x)$. Is that correct? - Jun 17th 2012, 05:14 PMskeeterRe: How to take limits of inverse functions!
- Jun 17th 2012, 05:15 PMProve ItRe: How to take limits of inverse functions!
I'm interested to know why this Algebra/Pre Calculus question was posted in Statistics...

- Jun 17th 2012, 05:33 PMskeeterRe: How to take limits of inverse functions!