# How to take limits of inverse functions!

• Jun 17th 2012, 02:36 PM
kwonypoo
How to take limits of inverse functions!
]How would you solve

lim as x -> infinity f-1( x2 + 2 x + 1)

?

Thanks!
• Jun 17th 2012, 03:06 PM
pickslides
Re: How to take limits of inverse functions!
Why not just find $f^{-1} (x^2+2x+1)$ ?
• Jun 17th 2012, 03:08 PM
skeeter
Re: How to take limits of inverse functions!
$f(x) = x^2 +2x + 1 = (x+1)^2$

restricting the domain of f(x) to x > -1

$f^{-1}(x) = \sqrt{x} - 1$

the inverse is unbounded as $x \to \infty$

I'm hoping you don't have confusion between inverse and reciprocal functions.
• Jun 17th 2012, 06:11 PM
HallsofIvy
Re: How to take limits of inverse functions!
What you wrote was $\lim_{x\to\infty} f^{-1}(x^2+ 2x+ 1)$ which we cannot help you with because you did not tell us what "f" is. Skeeter assumed you meant that $f(x)= x^2+ 2x+ 1$ and that you want to find $\lim_{x\to\infty} f^{-1}(x)$. Is that correct?
• Jun 17th 2012, 06:14 PM
skeeter
Re: How to take limits of inverse functions!
Quote:

Originally Posted by HallsofIvy
What you wrote was $\lim_{x\to\infty} f^{-1}(x^2+ 2x+ 1)$ which we cannot help you with because you did not tell us what "f" is. Skeeter assumed you meant that $f(x)= x^2+ 2x+ 1$ and that you want to find $\lim_{x\to\infty} f^{-1}(x)$. Is that correct?

that is another reason for my final statement ...
• Jun 17th 2012, 06:15 PM
Prove It
Re: How to take limits of inverse functions!
I'm interested to know why this Algebra/Pre Calculus question was posted in Statistics...
• Jun 17th 2012, 06:33 PM
skeeter
Re: How to take limits of inverse functions!
Quote:

Originally Posted by Prove It
I'm interested to know why this Algebra/Pre Calculus question was posted in Statistics...

not like it matters anymore ... the new owner/moderator hasn't been around for awhile. just note how many problems have been posted in the lobby.