question goes like this.

Food inspector examines 3 products in a group to determine if they are acceptable. From past experience it is known that the probability of finding no defects in the sample of 3 if 0.990, the probability of 1 defect in the sample of 3 is 0.006, and the probability of finding 2 defects in the sample of 3 is 0.003.

What is the probability of finding 3 defecting unites in the sample of 3??

I did .99 x .006 x .003 = .00001782 CLOSE but not the correct answer. I am not getting my stats class, something is not clicking. There is a piece of information that is not helping me connect all of this.

So what am I doing wrong?Or is it 3 times each number .99, .006, .003?

Any help would be great, thank you.

Jo