a couple plans to have three children. find the probability of getting exactly two boys and two girls i used binomial and got $\displaystyle \frac{3}{8}+\frac{3}{8}= \frac{3}{4} $ pls query me otherwise, thanks
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Originally Posted by lawochekel a couple plans to have three children. find the probability of getting exactly two boys and two girls i used binomial and got $\displaystyle \frac{3}{8}+\frac{3}{8}= \frac{3}{4} $ INCORRECT Reread your posting. There cannot be three children if exactly two boys and two girls. That is four. Which is it?
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