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Math Help - Question on rolling dice.

  1. #1
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    Question on rolling dice.

    I see the chart/table on rolling 2 dice, the outcomes.

    If when it asks for doubles, is it just 6 ways or 12. Because if you used a total of 6, you can have(4,2)(2,4)exc. So that means for each count of a sum of die, you double it correct? Like I said for doubles, if you have 6,6, it is reversed as well as 6,6. Which I know looks weird.

    Any help would be great, to get the wording down correctly.
    Jo
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  2. #2
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    Re: Question on rolling dice.

    Quote Originally Posted by bradycat View Post
    I see the chart/table on rolling 2 dice, the outcomes.
    If when it asks for doubles, is it just 6 ways or 12. Because if you used a total of 6, you can have(4,2)(2,4)exc. So that means for each count of a sum of die, you double it correct? Like I said for doubles, if you have 6,6, it is reversed as well as 6,6. Which I know looks weird.
    There is but one way to roll two six's. But two ways to roll a 2 and a 4.
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  3. #3
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    Re: Question on rolling dice.

    Hello, Jo!

    Consider this problem . . .

    A red die and a blue die are rolled.
    How many outcomes have a sum of 6?


    We can list the solutions:

    . . \begin{array}{cccccc}{\color{red}1} & {\color{blue}5} && \text{red 1, blue 5} \\ {\color{red}2} & {\color{blue}4} && \text{red 2, blue 4} \\ {\color{red}3}&{\color{blue}3} && \text{red 3, blue 3} & \text{(both are 3's)} \\ {\color{red}4}&{\color{blue}2}&& \text{red 4, blue 2} \\ {\color{red}5}&{\color{blue}1} && \text{red 5, blue 1}  \end{array}

    There are five solutions.


    But you might claim that there are six solutions
    . . by insisting that: . {\color{blue}3}\;\;{\color{red}3} \quad \text{blue 3, red 3} \quad\text{(both are 3's)}
    . . is yet another solution.

    Can you see that this is wrong?
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