# This is one question and can't come up with the answer.

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• May 25th 2012, 05:38 PM
bradycat
This is one question and can't come up with the answer.
At 1 school with 200 male students, 58 play football, 40 play basketball, and 8 play both. With the probability that a randomly selected male student plays neither sport?

What I am stuck on is the wording on how to calculate my total sum amount. 106 play sports, so do I subtract that from 200 to come up with 94 that don't play sports? I did all possible calculations and can't come up with the answer of .55.

Any help would be appreciated.
Thanks
Jo
• May 25th 2012, 06:08 PM
Bean
Re: This is one question and can't come up with the answer.
The 8 that play both are already accounted for in the 98 that play either so you subtract that number. You end up with 90 playing sports and 110 that don't. 110/200 = .55.
• May 25th 2012, 06:43 PM
bradycat
Re: This is one question and can't come up with the answer.
Thank you. I was not sure how to read that, but that makes sense. I am not use to the wording, so need to get comfy with it you know.