4.)13/221

6.)3/28

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- Feb 23rd 2006, 05:56 PM #1

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- Feb 23rd 2006, 06:10 PM #2

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Originally Posted by**Arbitur**

Number 4, that the probability of taking one club is $\displaystyle 13/52$, to take the next one since one was taken and one card less we have that $\displaystyle 12/51$.

Thus, $\displaystyle \frac{13}{52}\frac{12}{51}=\frac{1}{17}$

- Feb 23rd 2006, 06:13 PM #3

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- Feb 23rd 2006, 06:16 PM #4