# Am I right?- need to know thanks.

• February 23rd 2006, 05:56 PM
Arbitur
Am I right?- need to know thanks.
4.)13/221

6.)3/28
• February 23rd 2006, 06:10 PM
ThePerfectHacker
Quote:

Originally Posted by Arbitur
4.)13/221

6.)3/28

Number six is correct.

Number 4, that the probability of taking one club is $13/52$, to take the next one since one was taken and one card less we have that $12/51$.
Thus, $\frac{13}{52}\frac{12}{51}=\frac{1}{17}$
• February 23rd 2006, 06:13 PM
Arbitur
err. Can you show the math in between.
like the fractions multiplied then simplified im to stupid to do it
• February 23rd 2006, 06:16 PM
Arbitur
nevermind.