find the p(y<3.2) of the probability density function below

$\displaystyle f(x)= \frac{1}{8}(y+1) $ for 2<y<4

0 elsewhere

tried to solve the problem above by $\displaystyle \int\frac{1}{8}(y+1) $ at 0<y<3.2 as boundary, but got a value greater then 1 which i think is not possible. how should i

had gone about it? thanks