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Math Help - probability density function!

  1. #1
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    probability density function updated!

    find the p(y<3.2) of the probability density function below

     f(x)= \frac{1}{8}(y+1) for 2<y<4

    0 elsewhere

    tried to solve the problem above by  \int\frac{1}{8}(y+1) at 0<y<3.2 as boundary, but got a value greater then 1 which i think is not possible. how should i
    had gone about it? thanks
    Last edited by lawochekel; May 3rd 2012 at 07:54 AM. Reason: to correct
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  2. #2
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    Re: probability density function!

    Looks like you have not posted the complete question. It says 0 elsewhere, implying there was more information given somewhere.
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  3. #3
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    Re: probability density function!

    Quote Originally Posted by lawochekel View Post
    find the p(y<3.2) of the probability density function below

     f(x)= \frac{1}{8}(y+1)

    0 elsewhere

    tried to solve the problem above by  \int\frac{1}{8}(y+1) at 0<y<3.2 as boundary, but got a value greater then 1 which i think is not possible. how should i
    had gone about it? thanks
    That is not a probability function as written. You forgot to give the domain.
    Elsewhere, WHAT?
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  4. #4
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    Re: probability density function updated!

    Quote Originally Posted by lawochekel View Post
    find the p(y<3.2) of the probability density function below

     f(x)= \frac{1}{8}(y+1) for 2<y<4

    0 elsewhere
    You edited the OP.
    \int_2^{3.2} {f(y)dy}  = ?
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