Thread: the normal distribution question help

1. the normal distribution question help

Hi,

I am new here, and I hope you can help.

Here is the question:

One year, the distribution of salaries for professional sports players had mean $1.5 million and standard deviation$0.9 million. Suppose a sample of 400 major leagu0e players was taken. Find the approximate probability that the average salary of the 400 players that year exceeded $1.1 million. The correct answer is approximately 1, but I can't figure out how to work it out. So far I have tried resolving it by following z= 1,100,000-1,500,000/900,000 = 0.4 which according to the z table translates to .1554 Then I subtracted this number from .5 which resulted in .3446 which I take it to mean that approximately 34% of players earn more than 1.1million. How do I use the 400 baseball players in this equation? Thanks 2. Re: the normal distribution question help The standard deviation of sample means = 0.9/sqrt400 3. Re: the normal distribution question help 0.9 / sqrt(400) = 0.045 but...I still don't know how to solve the original question. How do I get to the answer that approximately 1 player's salary exceeds 1.1 million? Please be as explicit as possible. thanks. 4. Re: the normal distribution question help The question asks for the P that the average salary of 400 players exceeds 1.1 So we want P(Z> (1.1-1.5)/0.045) That is P(Z>-8.89) which from tables is approx. 1 5. Re: the normal distribution question help thank you so much Search tags for this page one year, the distribution of salaries for professional sports players had mean$1.6 million and standard deviation \$0.8 million. suppose a sample of 400 major league players was taken. find the approximate probability that the average salary of the 400 p

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