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Math Help - Poisson distribution

  1. #1
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    Poisson distribution

    A building has 2 independent automatc telephone exchanges A and B. The number X of wrong connections for A in any one day is a poisson variable with parameter 0.5 and the number Y of wrong connections for B in any one day is a poisson variable with parameter 1.

    Calculate in any particular day, the probability that there will be at most 3 wrong connections in the building given X≥2

    I tried using P(X=2)P(Y=0)+P(X=2)P(Y=1)+P(X=3)P(Y=0) but the answer was wrong
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  2. #2
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    Re: Poisson distribution

    looks fine to me.
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  3. #3
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    Re: Poisson distribution

    Let C be the event 'at most 3 wrong connections' and D the event X>or=2

    You are asked for P(CgivenD) for which the formula is P(C intersection D)/P(D) C intersection D meaning both C and D occur.
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