Thread: Venn Diagrams.. I need the theories

Could somebody answer these questions for me and give me the original formula...My online course did a terrible job on this section.. they dont tell you how to solve anything.

Originally Posted by Arbitur

Could somebody answer these questions for me and give me the original formula...My online course did a terrible job on this section.. they dont tell you how to solve anything.

Hello

to 14. 5 students don't have any specific signs, that leaves you with 40 student who could be tall or haired or both. The sum of 28+19 = 47. That means there are 7 students who are tall and haired. Than there are 28-7=21 who are haired but midgets and 19-7=12 who are tall (but bold).

I've attached a Venn diagram (for further information you may look at Euler diagram) to demonstrate the result.

Next problem will follow (I haven't much time now)

Greetings

EB

Second problem solution:

285 students attend both dances, so first dance attended 285 + 455 students and second attended 285 + 155. So total number of students who have been to both dances is 285+(455+155) which is 895 students.
Totally 605 students did not attend both dances.