Hi, can someone check this and tell me if I am doing this correctly? I would really appreciate it!

Six marbles are chosen without replacement from a box containing 10 red, 8 blue, and 3 yellow marbles. Let X be the number of blue marbles chosen.

a) Find the probability distribution of X.

b) Find the mean of the random variable X

ok so for part a i did:

P(0B) (6 choose 0) 1*(0.10)^0 (0.3)^6 = 0.000729

P(1B) (6 choose 1) 6* (0.10)^1 (0.3)^5 = .001458

P(2B) (6 choose 2) 15 *(0.10)^2 (0.3)^4 = .001215

P(3B) (6 choose 3) 20 *(0.10)^3 (0.3)^3 = 0.00054

P(4B) (6 choose 4) 15 * (0.10)^4 (0.3)^2 = 0.000135

P(5B) (6 choose 5) 6 * (0.10)^5 (0.3)^1 = 0.00000180

P(6B) (6 choose 6) 1 * (0.10)^6 (0.3)^0 = 0.00000010

Is this right? Or am I doing this completely wrong? Some of the numbers I calculated aren't coming out right