# A small question

• Mar 11th 2012, 01:48 PM
primeimplicant
A small question
Given P(A) , P(B) , and P(C) (along with other P(), i am just not providing them right now because they are a lot) are events of a random experiment.

Calculate P(A /\ B' /\ C')

Because i am not good with latex, i just scanned my work.

Please take a look and tell me ;-)

Imageshack - questionbg.png

Thanks!
• Mar 11th 2012, 02:22 PM
Plato
Re: A small question
Quote:

Originally Posted by primeimplicant
Given P(A) , P(B) , and P(C) (along with other P(), i am just not providing them right now because they are a lot) are events of a random experiment.
Calculate P(A /\ B' /\ C')

Looking at that image, I have no idea what you are doing there.
In order to Calculate P(A /\ B' /\ C') we need to know values.
• Mar 11th 2012, 02:29 PM
primeimplicant
Re: A small question
alright, these are the values, i scanned them as well.

Imageshack - givenvalues.png

but dont we need to do some work before we use the values ?

Is my explanation above completely wrong ?

thank you
• Mar 11th 2012, 02:49 PM
Plato
Re: A small question
Quote:

Originally Posted by primeimplicant
Imageshack - givenvalues.png
but dont we need to do some work before we use the values ?

If you expect to keep posting here, you must learn LaTeX,.

$P(A \cap B \cap C) + P(A \cap B' \cap C) = P(A \cap C)$

Use the scanned fromulas #4 & 7 to find $P(A \cap C)$
• Mar 11th 2012, 03:10 PM
primeimplicant
Re: A small question
Quote:

Originally Posted by Plato
If you expect to keep posting here, you must learn LaTeX,.
Yeah i know... sorry for the inconvenience caused.

Quote:

Originally Posted by Plato
$P(A \cap B \cap C) + P(A \cap B' \cap C) = P(A \cap C)$

Use the scanned fromulas #4 & 7 to find $P(A \cap C)$

Thanks a lot, it makes sense now , cheers