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Math Help - Probability for prizes!

  1. #1
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    Unhappy Probability for prizes!

    Hi all,
    Could someone help me with a problem please?

    I have 32 rounds and in each round there are 6 possible outcomes. Could someone please give the basic working of the probability of getting i.e. 5 out of 32 correct, or 10 out of 32 correct. Or even 5-9 out of 32, or 10-14 out of 32.
    Thanks

    Lee

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  2. #2
    MHF Contributor
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    Re: Probability for prizes!

    if only one of the 6 is correct, and you choose randomly, and the outcome of each round is independant of the other rounds, then...

    ...You are describing a case of the binomial distribution.

    With the following:
    probability of success (p) = 1/6
    probability of failure (q) = 5/6
    number of trials (n) = 32

    the chance of getting exactly X guesses right is given by the formula ^nC_r \times p^x \times q^{n-x}

    if you want to work out the chance of getting a range of values (5-10) then add up the chance of getting 5,6,7,8,9,10.

    There are online tools that calculate these for you: Binomial Calculator
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