Results 1 to 6 of 6

Math Help - Combinatorial Prob.

  1. #1
    Newbie
    Joined
    Dec 2011
    Posts
    12

    Combinatorial Prob.

    Suppose that there are 7 soccer players and 6 football players on a bus. Find the probability that a group of 5 players selected at random will consist of 3 soccer players and 2 football players.
    Follow Math Help Forum on Facebook and Google+

  2. #2
    Master Of Puppets
    pickslides's Avatar
    Joined
    Sep 2008
    From
    Melbourne
    Posts
    5,236
    Thanks
    29

    Re: Combinatorial Prob.

    From soccer players \binom{3}{7}

    From football players \binom{2}{6}

    In total \binom{5}{13}
    Follow Math Help Forum on Facebook and Google+

  3. #3
    Newbie
    Joined
    Dec 2011
    Posts
    12

    Re: Combinatorial Prob.

    Hi,Thank you for the help! the answer is the back of the book says it is .408. Would you mind explaining it please?
    Follow Math Help Forum on Facebook and Google+

  4. #4
    MHF Contributor alexmahone's Avatar
    Joined
    Oct 2008
    Posts
    1,074
    Thanks
    7

    Re: Combinatorial Prob.

    Quote Originally Posted by kangta27 View Post
    Hi,Thank you for the help! the answer is the back of the book says it is .408. Would you mind explaining it please?
    \frac{\dbinom{7}{3}*\dbinom{6}{2}}{\dbinom{13}{5}}  \approx 0.408
    Follow Math Help Forum on Facebook and Google+

  5. #5
    MHF Contributor alexmahone's Avatar
    Joined
    Oct 2008
    Posts
    1,074
    Thanks
    7

    Re: Combinatorial Prob.

    Quote Originally Posted by pickslides View Post
    From soccer players \binom{3}{7}

    From football players \binom{2}{6}

    In total \binom{5}{13}
    Hmmm ... each of those equals zero.
    Follow Math Help Forum on Facebook and Google+

  6. #6
    Master Of Puppets
    pickslides's Avatar
    Joined
    Sep 2008
    From
    Melbourne
    Posts
    5,236
    Thanks
    29

    Re: Combinatorial Prob.

    Quote Originally Posted by alexmahone View Post
    Hmmm ... each of those equals zero.
    As you can see, I'm having one of my upside down days!
    Follow Math Help Forum on Facebook and Google+

Similar Math Help Forum Discussions

  1. Combinatorial Prob.
    Posted in the Statistics Forum
    Replies: 3
    Last Post: September 8th 2012, 05:42 PM
  2. Replies: 2
    Last Post: April 12th 2011, 11:13 AM
  3. Combinatorial analysis
    Posted in the Discrete Math Forum
    Replies: 3
    Last Post: May 15th 2010, 06:02 AM
  4. combinatorial problem??
    Posted in the Number Theory Forum
    Replies: 2
    Last Post: September 23rd 2009, 11:29 PM
  5. combinatorial sum
    Posted in the Discrete Math Forum
    Replies: 3
    Last Post: May 12th 2009, 11:46 AM

Search Tags


/mathhelpforum @mathhelpforum