I'm not really good with probability, so excuse me if these are not completely correct.
For 1)Five of the counters are green, three are red.
We have 8 counters in total, the chances of drawing a green counter would be 5 out of 8, which is 62,5 %
When the 2nd counter is drawn, there are only 7 counters left.
Chances of drawing a red counter would then be 3 out of 7, which is a chance of 42,9%
The chances that the first one is green AND the second one is red is:
The chances of drawing two green counters are:
The chances of drawing two red counters are:
So the chances of drawing either a green pair, or a red pair is: