I'm not really good with probability, so excuse me if these are not completely correct.

For 1)
We have 8 counters in total, the chances of drawing a green counter would be 5 out of 8, which is 62,5 %

When the 2nd counter is drawn, there are only 7 counters left.

Chances of drawing a red counter would then be 3 out of 7, which is a chance of 42,9%

The chances that the first one is green AND the second one is red is:

%

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For 2)
The chances of drawing two green counters are:

%

The chances of drawing two red counters are:

%

So the chances of drawing either a green pair, or a red pair is:

%