Look at question 7 on the last page
so I know that for (ai)
H0: p = 0.2
H1: p <> 0.2 (does not equal)
Now when I carry out the test, if it was p>0.2 I would say
P(X>=9).... and then work out the answer
equall if it was p<0.2 I would say P(X<=9)
But given that it is p <>0.2 how do I carry out the test. Please can you explain as well!
For (b) I am again faced with the same issue
The distribution is
H1 again is p<>0.2
so for my normal approx to I use
P(x>=18) or p(x<=18)
I will continuty correct once I understand the principle
thanks for the help!