http://www.xtremepapers.com/Edexcel/...%202006-01.pdf

Look at question 7 on the last page

so I know that for (ai)

H0: p = 0.2

H1: p <> 0.2 (does not equal)

Now when I carry out the test, if it was p>0.2 I would say

P(X>=9).... and then work out the answer

equall if it was p<0.2 I would say P(X<=9)

But given that it is p <>0.2 how do I carry out the test. Please can you explain as well!

For (b) I am again faced with the same issue

The distribution is

X-N(20,16)

H1 again is p<>0.2

so for my normal approx to I use

P(x>=18) or p(x<=18)

I will continuty correct once I understand the principle

thanks for the help!