Independence of random variables X and X^2
If we have two r.v.: X = { -1, 0, 1 } and Y= 
, with X uniformly distributed with probability 1/3, then X and Y are independent, right?
Pdf values of Y are 2/3 if Y=1 and 1/3 if Y=0.
I can construct joint pdf with f(x, y), such that f(i, -1) = 0, f(i, 0) = 1/9 and f(i, 1) = 2/9. Then for every f(i, j), f(x, j) = f(x)f(y), and that is the definition of independence.
Am I missing something?
Re: Independence of random variables X and X^2
Saying 
and 'X and Y are independent' is 'a little contradiction'... isn't it?...
Kind regards
Re: Independence of random variables X and X^2
Yes, I have just understood that X's and Y's cannot be chosen independently.
