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Math Help - How to construct a 95% confidence interval for μd?

  1. #1
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    How to construct a 95% confidence interval for μd?

    Average scores for a test taken before learning the topic, then the results following:
    Before |12|18|25| 9 |14|16|
    After |18|24|24|14|19|20|

    The problem is: Construct a 95% confidence interval for μd.
    At the 1% significance level, can we conclude that the mean scores increase in the after category?

    I think I use the equation d +or- t* sd/sqrt n

    ∑dsquared=?
    ∑d=?
    n=6
    df=5
    C.I.=95
    alpha=.05
    I'm not sure if I'm doing it right any help would be greatly appreciated! I have an example of a similar one but I just want to know for sure if I'm on the right track. Thanks!
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  2. #2
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    Re: How to construct a 95% confidence interval for μd?

    If your significance is 1%, then \displaystyle \alpha =0.01 , do you understand why?

    If you are looking for an increase only then you need a one sided interval for the difference in mean.
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  3. #3
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    Re: How to construct a 95% confidence interval for μd?

    I think that they are two different questions though. Sorry I should have separated them. First, I'm supposed to construct a 95% confidence interval. Then after, I work out the same problem if alpha were 1%. But I'm just not sure if my equation is right. Have been staring at it for too long and I think I'm just making it harder than it is.
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