How to construct a 95% confidence interval for μd?

Average scores for a test taken before learning the topic, then the results following:

Before |12|18|25| 9 |14|16|

After |18|24|24|14|19|20|

The problem is: Construct a 95% confidence interval for μd.

At the 1% significance level, can we conclude that the mean scores increase in the after category?

I think I use the equation d +or- t* sd/sqrt n

∑dsquared=?

∑d=?

n=6

df=5

C.I.=95

alpha=.05

I'm not sure if I'm doing it right any help would be greatly appreciated! I have an example of a similar one but I just want to know for sure if I'm on the right track. Thanks!

Re: How to construct a 95% confidence interval for μd?

If your significance is 1%, then $\displaystyle \displaystyle \alpha =0.01$ , do you understand why?

If you are looking for an increase only then you need a one sided interval for the difference in mean.

Re: How to construct a 95% confidence interval for μd?

I think that they are two different questions though. Sorry I should have separated them. First, I'm supposed to construct a 95% confidence interval. Then after, I work out the same problem if alpha were 1%. But I'm just not sure if my equation is right. Have been staring at it for too long and I think I'm just making it harder than it is.