"A bag contains 3 red balls, 4 yellow balls, and 5 white balls. If two balls are being drawn from the bag without replacement, what is the probability that the first ball is yellow and the second ball is white?"
So I know that to calculate the probability of drawing two balls you calculate the individual probability of drawing each ball then multiply them together. But do I need to do any additional calculations for the probability that they are drawn in the correct order (first is red, second is white)? If so, what equation would I use to do that? Or am I over-thinking this?
No, that's all you need to do. Initially there are 3 red balls, 4 yellow balls, and 5 white balls for a total of 12 balls. The probability of drawing a yellow ball is 4/12= 1/3. Once that is done, there are 3 red balls, 3 yellow balls, and 5 balls for a total of 11 balls. The probability of drawing a white ball is 5/11. Yes, multiply them together.