Thread: Quick question

Quick question.

I have $5 in mixed coins in a bag. The coins are either 5c, 10c or 50c and I have calculated the following probabilities.

P(5c) = 4/8
P(10c) = 3/8
P(50c) = 1/8

Any thoughts on how to go about finding how many of each coin there are?

Let the total number of coins be n. Then the number of 5c coins is 4n/8, etc.

The probabilities give a ratio of coins to each other:

4 nickles = $.20 3 dimes = $.30 and 1 Fifty cent is .50$

add these up and you get $1.00 dollar. So you would need five of the above groups!