if a nine digit no is formed using 1 to 9 without repetition and if the probability that they will be divisible by 11 is p/q then p+q=

can yu tell me the divisibility of 11

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- November 13th 2011, 10:10 AMprasum9 digit no., prob divisible by 11 is p/q. Find p+q.
if a nine digit no is formed using 1 to 9 without repetition and if the probability that they will be divisible by 11 is p/q then p+q=

can yu tell me the divisibility of 11 - November 13th 2011, 10:28 AMveileenRe: prob
A number is divisible by 11 if the difference between the sum of the digits in the odd positions counting from the left (the first, the third ...) and the sum of the remaining digits is divisible by 11.

For example:

1.**5**8**5**6**4**

The sum of the digits in the odd positions counting from the left is 5+5+4=14

The sum of the remaining digits is 8+6=14

14-14=0, and 0 is divisible by 11, so 58564 is divisible by 11 too.

2.**6**3**5**0**4**7

The sum of the digits in the odd positions counting from the left is 6+5+4=15

The sum of the remaining digits is 3+0+7=10

15-10=5, 5 isn't divisible by 11, so 635047 isn't divisible by 11. - November 14th 2011, 01:36 AMprasumRe: 9 digit no., prob divisible by 11 is p/q. Find p+q.
how to do this problem

in probability