1. ## Permu

let A be a set of 4 digit nos a1,a2,a3,a4 where a1>a2>a3>a4, then n(A) is equal to

2. ## Re: Permu

This can be solved by using combination. Make this a function where X={a1,a2,a3,a4} and Y={0,1,2,...9}. All you have to do is pick 4 numbers from Y. You dont even need to think about the order because the biggest number automatically becomes a1 and the smallest number becomes a4.

3. ## Re: Permu

Hello, prasum!

Very sloppy wording . . .

$\text{Let }A\text{ be a set of 4-digit numbers}$ composed of the digits $\{a_1,a_2,a_3,a_4\}$
$\text{ where }a_1>a_2>a_3>a_4,$ and each digit is used once.

$\text{ Find }n(A).$

* .The problem said that the 4-digit numbers are: . $a_1, a_2, a_3, a_4.$
. . Therefore:. $n(A) \,=\,4.$ . (duh!)

* .If the digits can be repeated:. $n(A) \:=\:4^4 \:=\:256.$

Having said all that:. $n(A) \,=\,4!\,=\,\boxed{24}$

BTW the inequality was given to indicate that the digits are distinct.

If the digits were $\{2,7,7,9\}$ or $\{3,3,3,8\}$, the answers would "depend".

4. ## Re: Permu

Originally Posted by prasum
let A be a set of 4 digit nos a1,a2,a3,a4 where a1>a2>a3>a4, then n(A) is equal to
I think that reply #2 is correct.
This question is about what is known as strictly sorted natural numbers with descending digits.
Example: 7421 and not 7412.
Any set of four distinct digits corresponds to a strictly sorted natural number with descending digits.

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### Let A be the set of four-digit numbers a1, a2, a3, 04, where a1> a2 > a3 > a4, then how many values of A are possible?

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