Thread: probability

Originally Posted by chocolatelover

Hi everyone,

Can someone help me with this probability problem, please?

The following frequency distribution reports the higest education level achieved by Standard and Poor's top 500 CEOs.

No college-14
B.S./B.A.-164
M.B.A.-191
J.D.-50
Other-81

find the probability that a randomly selected CEO from Standard and Poor's top 500 achieved the educational level of

a. B.S./B.A.

I thought that I needed to take 164/500, since if you add them all up it equals 500. So, I got .328 Is this correct? If it isn't, can you show me what I need to do, please?

b. either M.B.A. or J.D.
Would I take 191+50/500????

c. at least some college
Would I add up all the numbers except the one for "no college"?

Thank you very much

Looks OK to me but you should use brackets for (191+50)/500

RonL