Originally Posted by
Robertf1 Imagine i have a box or anything which is full with x sheets of paper. 1 sheet is different from others. I have x attempts to take blindly one sheet. What is the formula after which i can know what is the percentage of getting 'the different sheet' at least once? (If i have taken out a sheet i must put it back before next attempt!).
As I figured out if
x=2 then 1/2+1/2*1/2=75%
x=3 then 1/3+1/3*1/3+1/3*1/3*1/3 (right?)
So it means 1/x+1/x*1/x+...+(1/x)^x, but how to write it shorter, cause obviously if x=37 its big work to get result.