# picking numbers

• Oct 12th 2011, 08:13 AM
Veronica1999
picking numbers
Bernardo randomly picks 3 distinct numbers from the set {1, 2, 3, 4, 5, 6, 7, 8, 9} and arranges them in descending order to form a 3-digit number. Silvia randomly
picks 3 distinct numbers from the set {1, 2, 3, 4, 5, 6, 7, 8} and also arranges
them in descending order to form a 3-digit number. What is the probability that
Bernardo’s number is larger than Silvia’s number?

The answer is 37/56.

The problem seems simple but i keep on getting the wrong answer.....
• Oct 12th 2011, 08:52 AM
Plato
Re: picking numbers
Quote:

Originally Posted by Veronica1999
Bernardo randomly picks 3 distinct numbers from the set {1, 2, 3, 4, 5, 6, 7, 8, 9} and arranges them in descending order to form a 3-digit number. Silvia randomly
picks 3 distinct numbers from the set {1, 2, 3, 4, 5, 6, 7, 8} and also arranges them in descending order to form a 3-digit number. What is the probability that Bernardo’s number is larger than Silvia’s number?
The answer is 37/56.

I get $\frac{83}{168}$.
Is that what you get?