Independent Events Question
I am having a bit of trouble with finding the answer to this question.
Students A, B, C each independently on a test. The probability of A getting the right answer is 0.9, for B it is 0.7 and for C it is 0.4.
If two of them get the right answer, what is the probability that C got their question wrong.
My logic behind this was finding AB(Not C) = 0.9*0.7*0.6, but apparently this is wrong. The correct answer was 0.7354
Any insight would be much appreciated. THanks!
Re: Independent Events Question
It is conditional probability. You need to divide your answer by the probability that two of them got the right answer .....
Originally Posted by KelvinScale