Very well!...we write the difference equation as...
$\displaystyle \Delta_{n}= p_{n-1}-p_{n}= .24\ p_{n}-2000= f(p_{n})$ (1)
... and neceesary it is 'started' by an 'initial condition' $\displaystyle p_{0}=p$. The procedure for solving a difference equation of the type (1) is described in...
http://www.mathhelpforum.com/math-he...-i-188482.html
In Your case the f(x) has only one zero in $\displaystyle x_{0}=8333.33...$ but, because is $\displaystyle f^{'}(x_{0})>0$ , $\displaystyle x_{0}$ is a
repulsive fixed point and that means that $\displaystyle x_{0}$ is a
unstable equilibrium point. In other words, for $\displaystyle p=x_{0}$ the solution of (1) is the constant sequence $\displaystyle p_{n}=x_{0}$, but for all other p the solution will diverge...
Kind regards
$\displaystyle \chi$ $\displaystyle \sigma$