This isn't a homework problem that I need help with or anything of that nature. This is more of a personal math-related problem.

I play a collectable card game, and I am trying to determine which of my decks would benefit the most from a certain rare card that I possess. As part of this analysis I am trying to figure out the probability of drawing certain cards needed for turn-one or turn-two combos that can be played only if I draw the rare card in question. In all likelihood I cannot remotely rely upon these cards being in my opening hand with any reliability given the fact that the chances of drawing a five or six card combo will be ludicrously low, so this is really something I am looking at more for fun than anything else.

I already know the probabilities of drawingoneof the given cards of a combo in question in a seven card opening hand, but unfortunately the course I took that dealt with probability did not deal with anything as complex as figuring out the odds of having multiple events occur at once. Even if it did I no longer own the textbook and it was years ago.

Let's say that one of the combos requires five specific cards in an opening hand of seven cards, and the probabilities of drawing each card on the first card drawn are as follows:

- Card 1 (the rare card in question): 1/60 chance of being drawn
- Card 2: 21/60 chance of being drawn. Two of this card in an opening hand are required for the combo, so the probability of a second one being drawn ranges from 20/59 to 20/54 depending on the number of cards drawn so far
- Card 4: 4/60 chance of being drawn
- Card 5: 3/60 chance of being drawn

Obviously the probability of drawing one of the desired cards increases with each card drawn. Additionally, only five out of seven cards in an opening hand need to be the desired cards. The other two cards drawn can be anything without affecting the combo's success. Finally, the five cards can be drawn in any order without affecting the combo's success.

Most of the combos I am looking at are five cards, but there is one that requires six cards (which has eight drawn cards instead of seven to draw from since it is a second-turn combo) and a couple that require four cards. I am hoping that whatever solution I am looking for can somehow be applied to any number of needed cards.

I'm afraid that I am wholly unsure of where to begin, and I'm hoping that the solution I am looking for is not horribly complicated.

Thank you!