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**puggles** Two events E and F ; the probability that neither is true is 0.6, the probability that both are true is 0.2; find the probability that exactly one of E or F is true.

So I started the problem with P(not E and not F)=.6, which means that P(E or F) = 1-.6=.4 and P(E and F) = .2

Exactly one is true is P(E\F) = P(E) - P(E and F), right? (or with P(F\E))

and by the laws of probability we have: P(E or F ) = P(E) + P(F) - P(E and F) working the math down, I got to P(E) + P(F) = .6

At this point I'm stuck, I don't know where to go from here to figure out P(E\F). Any help would be greatly appreciated!