I know how to solve this problem using the Choose method,
but I'm trying to do it this way and running into a problem.
Could someone see where I'm going wrong?
Given a deck of 52 cards, what is the probability of drawing
. . an Ace, a Two, a Three, a Four, and a Five?
My answer: .(4/52) * (4/51) * (4/50) * (4/49) *(4/48) because you have
a 4/52 chance of drawing the Ace, then a 4/51 chance of the Two, and so on.
You have imparted an order to the cards.
You have insisted that the first card is an Ace, the second is a Two, and so on.
There are possible orders to the five cards.
The answer is times your answer.