Hello, Relmiw!

I know how to solve this problem using the Choose method,

but I'm trying to do it this way and running into a problem.

Could someone see where I'm going wrong?

Given a deck of 52 cards, what is the probability of drawing

. . an Ace, a Two, a Three, a Four, and a Five?

My answer: .(4/52) * (4/51) * (4/50) * (4/49) *(4/48) because you have

a 4/52 chance of drawing the Ace, then a 4/51 chance of the Two, and so on.

You have imparted anto the cards.order

You have insisted that the first card is an Ace, the second is a Two, and so on.

There are possible orders to the five cards.

The answer is times your answer.