I don't know how to do this question. Can someone help me?
There are 3 boys and 9 girls. But there are only 5 seats. The 3 boys must sit in the middle. The leftover seats are for the girls. How many ways can this be arranged?
So there are 6 ways in which i can arrange the boys in the middle
And there are 6 x 6P1 = 36 ways in which a girl sit next to the first boy
Then, there are 36 x 5P1 = 180 ways in which another can sit next to the last boy
Is that right?