Difficult Normal Distribution question

X is normally distributed with mean where the mean is greater than zero
If
what is the closest decimal approximation for the value
???
a:0.025
b:0.05
c:0.475
d:0.4875
e:-0.025 (obviously wrong choice, just provided for question completeness)

I would rewrite the probability:

This looks like a good approach, except how do I find Pr(x<-a)? Pr(X< mu) is obviously 0.5, but this alone doesn't allow me to solve the question...?
Thanks in advance.

Notice

This approach gives the answer as c above, but how does P(x<-a)=P(x>a) hold true even when mean is not zero?

Because the graph of normal distribution is symmetric.

Symmetric about the mean, hence P(X<mu-b) would be equal to P(X>mu+b) for any b but if mu is not zero then P(x<-b) would not equal P(x>b) for an b. Or is there a flaw in this logic? Hmmm...