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Math Help - success arrangement

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    success arrangement

    in how many letters of SUCCESS can be arranged such that no two C or no two S are together.
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    Re: success arrangement

    Quote Originally Posted by ayushdadhwal View Post
    in how many letters of SUCCESS can be arranged such that no two C or no two S are together.
    Let \mathcal{S} be the set of all rearrangements in which no to S's are together.

    Let \mathcal{C} be the set of all rearrangements in which no to C's are together.

    The number in \mathcal{C} is \|\mathcal{C}\|=\binom{6}{2}\frac{5!}{3!}.

    Now you must calculate \|\mathcal{C}\cup\mathcal{S}\|.
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