At XYZ high school there is a 18% drop-out rate for seniors. If six seniors are randomly selected, what is the probability that one will drop out of high school?
Last edited by mr fantastic; Aug 11th 2011 at 05:36 AM.
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Sounds like a binomial question to me.
P(1) = 6C1 (0.18)^1(1-0.18)^(6-1)
Can it be like this:
E = np
1 = 6 x p
p = 1/6
No, that is the expected value of how many students out of 6 will drop out, which will be
np = 6 x 0.18 = 1.08, you are after the probability of 1 student dropping out when there are 6 students.
Thank you...got it....
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