please give me a clue for the following question..
There is 50% chance that any bomb may hit the target. Two direct hits are required to destroy the target completely. How many bombs must be dropped for 99% chance?
Thanks in advance....
please give me a clue for the following question..
There is 50% chance that any bomb may hit the target. Two direct hits are required to destroy the target completely. How many bombs must be dropped for 99% chance?
Thanks in advance....
The solution of the problem is the solution of the 'equation'...
$\displaystyle 1-\sum_{k=0}^{1} \binom{n}{k}\ p^{k}\ (1-p)^{n-k} = .99$ (1)
... where $\displaystyle p=\frac{1}{2}$ and $\displaystyle n$ is the 'unknown quantity'...
Kind regards
$\displaystyle \chi$ $\displaystyle \sigma$