Hello, procrastinator!

With "dice" problems, there are no neat formulas.

Usually, we must list the outcomes (or visualize them).

I assume we are to find and .The number showing on the upper faces when two fair six-sided dice are tossed, is observed.

Consider events A and B

A: the total score is at most 5

B: at least one die achieves a score of 3 or 4

(1) There are: . possible outcomes.

There are 10 outcomes with a sum of 5 or less:

. .

Therefore: .

(2) I have a "back door" approach to the second part.

The probability that a die doesnotshow a 3 or 4 is: .

The probability that neither die shows a 3 or 4 is: .

Therefore, the probability that at least one die shows a 3 or 4 is:

. .