P-Value/ One-or Two Tailed.
Having a tough time with me homework on P-Value. If anyone could help solve this?
According to an article in The New York Times, 19.3% of New York City adults
smoked in 2003. Suppose that a survey is conducted this year. 8 out of 80 randomly chosen New York City residents reply that they smoke. At a significance level of 0.05, test the claim that the rate is still 19.3%.
1. Identify H0, Ha.
A) H0: p = 0.193 vs. Ha: p > 0.193
B) H0: p = 0.1 vs. Ha: p < 0.1
C) H0: p = 0.1 vs. Ha: p > 0.1
D) H0: p = 0.193 vs. Ha: p < 0.193
E) H0: p = 0.193 vs. Ha: p ≠ 0.193
2. Compute the test statistic. (2 decimal places)
A. 1.08 B. – 1.08 C. – 2.11 D. 2.11 E. None of the others
3. Compute the P-value. (4 decimal places)
A. 0.9826 B. 0.0174 C. 0.9890 D. 0.0348 E. None of the others
4. At a significance level of 0.05, does the sample provide sufficient evidence to reject that the percent of smokers in New York City is still 19.3%?
A. yes B. no C. more information is needed to determine
5. If the actual rate is 23.1%, what type of error does it introduce?
A. Type I Error B. Type II Error C. No Error
Re: P-Value/ One-or Two Tailed.
Quote:
Originally Posted by
mathwiz1 
Having a tough time with me homework on P-Value. If anyone could help solve this?
According to an article in The New York Times, 19.3% of New York City adults
smoked in 2003. Suppose that a survey is conducted this year. 8 out of 80 randomly chosen New York City residents reply that they smoke. At a significance level of 0.05, test the claim that the rate is still 19.3%.
1. Identify H0, Ha.
A) H0: p = 0.193 vs. Ha: p > 0.193
B) H0: p = 0.1 vs. Ha: p < 0.1
C) H0: p = 0.1 vs. Ha: p > 0.1
D) H0: p = 0.193 vs. Ha: p < 0.193
E) H0: p = 0.193 vs. Ha: p ≠ 0.193
2. Compute the test statistic. (2 decimal places)
A. 1.08 B. – 1.08 C. – 2.11 D. 2.11 E. None of the others
3. Compute the P-value. (4 decimal places)
A. 0.9826 B. 0.0174 C. 0.9890 D. 0.0348 E. None of the others
4. At a significance level of 0.05, does the sample provide sufficient evidence to reject that the percent of smokers in New York City is still 19.3%?
A. yes B. no C. more information is needed to determine
5. If the actual rate is 23.1%, what type of error does it introduce?
A. Type I Error B. Type II Error C. No Error
Well both D and E are defendable, but given 5. I guess you are expected to choose E.
Now what have you done and what problems are you having, are those numbers in 2,3, and 4 your computations, ..
CB
