1. ## Density function problem?

I'm not even sure if that's the proper thing to call it, but here's the question.

A point is uniformly distributed within the disk of radius 1. That is, its density is
f(x,y)=C, 0≤x^2+y^2≤1
Find the probability that its distance from the origin is less than x, 0≤x≤1.

I'm not sure of what I'm supposed to do here. What are my steps?

2. ## Re: Density function problem?

Originally Posted by downthesun01
I'm not even sure if that's the proper thing to call it, but here's the question.

A point is uniformly distributed within the disk of radius 1. That is, its density is
f(x,y)=C, 0≤x^2+y^2≤1
Find the probability that its distance from the origin is less than x, 0≤x≤1.

I'm not sure of what I'm supposed to do here. What are my steps?
The requested probability is the ratio between the area of a circle af radious $\rho$ and the circle of radious 1...

$P \{d < \rho\} = \frac{\pi\ \rho^{2}}{\pi}= \rho^{2}$

Kind regards

$\chi$ $\sigma$

3. ## Re: Density function problem?

I still don't understand the question. I'm trying to picture it right now.

There's a point that's uniformly distributed within a circle that has a radius of 1, and I'm supposed to find the probability that the point's distance from the origin of the circle is less than x.

I don't understand where this second circle with a radius of rho comes from.

I can solve for C. That seems rather straightforward.

$1=\int \int_R Cdxdy=c\pi r^2=c\pi$
$c=\frac{1}{\pi}$

But from there I'm pretty confused. If someone could offer some insight, I'd appreciate it. Thanks

What does $c=\frac{1}{\pi}$ mean? Is it the probability that the point occupies a certain spot in the circle?

And what is x supposed to be?