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a survey is carried out on a computer network.the probability that a log on to the network is succesful is 0.97.find the probabilty that exactly six out of eight users that attempt to log on will do so successfully.
x is bin(8, 0.97)
P[6] = C(8,6) * 0.97^6 * 0.03^2 = 0.0209908945242108 is this correct or am i doing this completely wrong???
Sounds good to me.Quote:
Originally Posted by university
The number of significant figures given is - sorry - absurd. Most questions state the accuracy required - check the question and round your answer accordingly.Quote:
Originally Posted by university
No need to check the question the clue is in the precision of the log-on probability. This is given to two significant figures, no naively we might expect that we should give the answer two significant figures or 0.021.Quote:
Originally Posted by mr fantastic
But wait I hear you cry, a probability of 0.97 indicates a range of possible values of 0.965 to 0.975 (give or take an end point). That gives a range for the answer of 0.0277 to 0.0150, so we have at best only one significant figure, so the answer should be truncated to 0.02.
CB
Aha .... but maybe the log-on probability is - unbelievably, perhaps - an exact probability ....Quote:
Originally Posted by CaptainBlack
I'm sure that would violate some rule about how it should be written, but which I don't know!? :(Quote:
Originally Posted by mr fantastic
CB