Don't quote odds here, they mean different things in different contexts

OK now we have probabilities of 0.46 for 3 or more goals and 0.54 of 2 or fewer goals.the no commission implied probability is

1/2.12=0.47

1/1.802=0.55

=0.47/0.47+0.55=0.46

The equation you need to solve is:then use the poisson formula here

i guess P < 3 = 0.54

x = 0, 1, 2

e = 2.71828

μ is ur answer

P(x; μ) = (e^-μ) (μ^x) / x!

so u need 0.54=[(2.71828^-μ) (μ^0) / 0!]+[(2.71828-μ) (μ^1!) / 1]+[(2.71828^-μ) (μ^2) / 2!]

can any1 help me solve this or even better where can i find a formula for the mean.

would be amazing if there was something i could use in excel to solve this also.

many thanks

This almost certainly has no simple closed form solution for so you will need to solve it numerically (or graphically).

CB