Re: Help solve this probability question

Quote:

Originally Posted by

**SLJSWW** a) it receives less than 3 claims in a given month;

Make $\displaystyle \displaystyle \lambda = 3$ and find $\displaystyle \displaystyle P(x<3) = P(x=0)+P(x=1)+P(x=2)$

where $\displaystyle \displaystyle P(x=k) = \frac{\lambda^k\times e^{-\lambda}}{k!}$

Quote:

Originally Posted by

**SLJSWW**

b) it receives more than 2 more in a given three month period

for a 3 month period make $\displaystyle \displaystyle \lambda = 3\times 3$ and find $\displaystyle \displaystyle P(x>2) = 1-P(x\leq 2) $

where $\displaystyle \displaystyle P(x=k) = \frac{\lambda^k\times e^{-\lambda}}{k!}$