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Math Help - The probability distribution, how to solve it?

  1. #1
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    The probability distribution, how to solve it?

    The probability distribution of the random variable X that describes the number of cars sold by a dealer is weekly

    X 0 1 2 3 4 5 6 7 8
    P [X = k] p 0.04 0.04 0.11 0.30 0.23 0.10 0.05 0.03

    a) What is the average number of cars sold per week?, What is the most likely?
    b)What is the probability that the number of cars sold in a week is more than 2 but less than 5?, What is the maximum number of cars sold weekly with a probability of 50%?,
    c) If the middle of a week the number of cars sold is less than 3,
    What is the probability that at week's end the average overcome?

    a) the average it will be 0 * 0.04 +0.04 * 1. .0,03 * 8 = 4.11
    most likely from the histogram I read that the value 1/2 is for 4
    b) add the probability histogram between 2 and 5 (excluding Fridays: 0.1 0.11 0.30 = 0.51)?
    I do not know how to check the max number of cars with a probability of 50%?
    c) I have no idea
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  2. #2
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    Re: The probability distribution, how to solve it?

    b) Find the probability of P(3)+P(4)

    c) Find \displaystyle P(X=4.11|X<3) = \frac{P(X=4.11\cap X<3)}{P(X<3)}
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  3. #3
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    Re: The probability distribution, how to solve it?

    Thank You for help I will try now to solve this and copy my results.

    But i want to ask about:
    What is the maximum number of cars sold weekly with a probability of 50%?,

    a)
    average=0*0,04+1*0,04+2*0,1+3*0,11+4*0,3+5*0,23+6*  0,1+7*0,05+8*0,03=4,11

    b)
    P(B)=P(3)+P(4)=0,11+0,3=0,41

    c)
    P(X<3)= \0,04+0,04+0,1=0,18

    P(X=4,11)=0,5

    how to do this?

    P(X=4,11|X<3)= \frac{0,5*XXX}{0,04+0,04+0,1}=
    Last edited by piotr580; June 20th 2011 at 05:04 PM.
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