1. ## Dice Roll Problem

If I were to roll 5 6 sided dice (5D6), then what is the probability of me rolling the following 5 numbers: 1,2,3,4,5 ? Basically, what is the probability of not rolling either a six or a double on 5 dice? Thank you in advance for your help!

EDIT: I'd prefer the answer as a percentage rather than a decimal if possible!

2. Originally Posted by mathhelp2012
If I were to roll 5 6 sided dice (5D6), then what is the probability of me rolling the following 5 numbers: 1,2,3,4,5 ? Basically, what is the probability of not rolling either a six or a double on 5 dice? Thank you in advance for your help!
EDIT: I'd prefer the answer as a percentage rather than a decimal if possible!
There are $\displaystyle 6^5$ possible outcomes.
There are $\displaystyle 5!=120$ that contain the numbers $\displaystyle 1,2,3,4,\& 5$.

3. Originally Posted by Plato
There are $\displaystyle 5!=120$ that contain the numbers $\displaystyle 1,2,3,4,\& 5$.
But how many of these are doubles (doubles including trebles, quadruples, quintuples etc.)?

4. Originally Posted by mathhelp2012
But how many of these are doubles (doubles including trebles, quadruples, quintuples etc.)?
None of them.
Each of the 120 outcomes contains exactly one each of $\displaystyle 1,2,3,4,5$.

5. Thanks! So there is a 1.54% chance of getting exactly one each of 1,2,3,4 and 5?

6. You were told the probability of getting 1-2-3-4-5 (any order) is 120/7776 :
isn't that enough?