Probability using distribution(lambda)?

**Kimberly** · May 17th 2011, 06:16 AM

Thank you for reading! In this exercise, I think the lambda sign threw me off.

Here's the problem:

The number of monthly repairs on a computer (I'm guessing it was a PC, lol!) is a random variable that has the distribution with $\lambda = 5.5$ . Find the probability that the computer works for a month:

a) without need for repairs
b) with need of two repairs

Is it THIS formula? ==> $f(x,\lambda) = \frac{\lambda^x e^{-\lambda}}{x!}$

If so, what would $e$ be? I'm assuming that $\lambda$ is given (=5.5) and I'm guessing $x$ is the number of repairs needed on the computer (which would be $x!=0!$ on "a" and $x!=2!$ on "b").

Thank you for all your help!

**TheEmptySet** · May 17th 2011, 06:35 AM

This is called the Poisson distribution!

See this link and then show us what you have tried.

Poisson distribution - Wikipedia, the free encyclopedia

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