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Thread: Probability using distribution(lambda)?

  1. #1
    Dec 2008

    Probability using distribution(lambda)?

    Thank you for reading! In this exercise, I think the lambda sign threw me off.

    Here's the problem:

    The number of monthly repairs on a computer (I'm guessing it was a PC, lol!) is a random variable that has the distribution with $\displaystyle \lambda = 5.5$. Find the probability that the computer works for a month:

    a) without need for repairs
    b) with need of two repairs

    Is it THIS formula? ==> $\displaystyle f(x,\lambda) = \frac{\lambda^x e^{-\lambda}}{x!}$

    If so, what would $\displaystyle e$ be? I'm assuming that $\displaystyle \lambda$ is given (=5.5) and I'm guessing $\displaystyle x$ is the number of repairs needed on the computer (which would be $\displaystyle x!=0!$ on "a" and $\displaystyle x!=2!$ on "b").

    Thank you for all your help!
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  2. #2
    Behold, the power of SARDINES!
    TheEmptySet's Avatar
    Feb 2008
    Yuma, AZ, USA
    This is called the Poisson distribution!

    See this link and then show us what you have tried.

    Poisson distribution - Wikipedia, the free encyclopedia
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