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Math Help - Probability using distribution(lambda)?

  1. #1
    Dec 2008

    Probability using distribution(lambda)?

    Thank you for reading! In this exercise, I think the lambda sign threw me off.

    Here's the problem:

    The number of monthly repairs on a computer (I'm guessing it was a PC, lol!) is a random variable that has the distribution with \lambda = 5.5. Find the probability that the computer works for a month:

    a) without need for repairs
    b) with need of two repairs

    Is it THIS formula? ==> f(x,\lambda) = \frac{\lambda^x e^{-\lambda}}{x!}

    If so, what would e be? I'm assuming that \lambda is given (=5.5) and I'm guessing x is the number of repairs needed on the computer (which would be x!=0! on "a" and x!=2! on "b").

    Thank you for all your help!
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  2. #2
    Behold, the power of SARDINES!
    TheEmptySet's Avatar
    Feb 2008
    Yuma, AZ, USA
    This is called the Poisson distribution!

    See this link and then show us what you have tried.

    Poisson distribution - Wikipedia, the free encyclopedia
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